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divisionapproximateQuadraticArcLengthfontTools.misc.bezierTools.approximateQuadraticArcLengthapproximateQuadraticArcLengthCfontTools.misc.bezierTools.approximateQuadraticArcLengthCcalcQuadraticBoundsfontTools.misc.bezierTools.calcQuadraticBoundsapproximateCubicArcLengthfontTools.misc.bezierTools.approximateCubicArcLengthapproximateCubicArcLengthCfontTools.misc.bezierTools.approximateCubicArcLengthCcalcCubicBoundsfontTools.misc.bezierTools.calcCubicBoundssplitLinefontTools.misc.bezierTools.splitLinesplitQuadraticfontTools.misc.bezierTools.splitQuadraticfontTools.misc.bezierTools.splitQuadratic.genexpr.0genexprsplitCubicfontTools.misc.bezierTools.splitCubicfontTools.misc.bezierTools.splitCubic.genexprsplitQuadraticAtTfontTools.misc.bezierTools.splitQuadraticAtTsplitCubicAtTfontTools.misc.bezierTools.splitCubicAtTsplitCubicAtTCfontTools.misc.bezierTools.splitCubicAtTCcan't send non-None value to a just-started generatorsplitCubicIntoTwoAtTCfontTools.misc.bezierTools.splitCubicIntoTwoAtTC_splitQuadraticAtTfontTools.misc.bezierTools._splitQuadraticAtT_splitCubicAtTfontTools.misc.bezierTools._splitCubicAtT_splitCubicAtTCfontTools.misc.bezierTools._splitCubicAtTCfontTools.misc.bezierTools.__defaults__solveQuadraticfontTools.misc.bezierTools.solveQuadraticsolveCubicfontTools.misc.bezierTools.solveCubiccalcQuadraticParametersfontTools.misc.bezierTools.calcQuadraticParameterscalcCubicParametersfontTools.misc.bezierTools.calcCubicParametersfontTools.misc.bezierTools.calcCubicParametersCcalcQuadraticPointsfontTools.misc.bezierTools.calcQuadraticPointscalcCubicPointsfontTools.misc.bezierTools.calcCubicPointsfontTools.misc.bezierTools.calcCubicPointsClinePointAtTfontTools.misc.bezierTools.linePointAtTquadraticPointAtTfontTools.misc.bezierTools.quadraticPointAtTcubicPointAtTfontTools.misc.bezierTools.cubicPointAtTcubicPointAtTCfontTools.misc.bezierTools.cubicPointAtTCsegmentPointAtTfontTools.misc.bezierTools.segmentPointAtT_line_t_of_ptfontTools.misc.bezierTools._line_t_of_pt_both_points_are_on_same_side_of_originfontTools.misc.bezierTools._both_points_are_on_same_side_of_originlineLineIntersectionsfontTools.misc.bezierTools.lineLineIntersections_alignment_transformationfontTools.misc.bezierTools._alignment_transformation_curve_line_intersections_tfontTools.misc.bezierTools._curve_line_intersections_tfontTools.misc.bezierTools._curve_line_intersections_t.genexprcurveLineIntersectionsfontTools.misc.bezierTools.curveLineIntersections_curve_boundsfontTools.misc.bezierTools._curve_bounds_split_segment_at_tfontTools.misc.bezierTools._split_segment_at_t_curve_curve_intersections_tfontTools.misc.bezierTools._curve_curve_intersections_tmidpointfontTools.misc.bezierTools._curve_curve_intersections_t.midpointlambda3fontTools.misc.bezierTools._curve_curve_intersections_t.lambda3precision_is_linelikefontTools.misc.bezierTools._is_linelikefontTools.misc.bezierTools._is_linelike.genexprcurveCurveIntersectionsfontTools.misc.bezierTools.curveCurveIntersectionssegmentSegmentIntersectionsfontTools.misc.bezierTools.segmentSegmentIntersections_segmentreprfontTools.misc.bezierTools._segmentreprfontTools.misc.bezierTools._segmentrepr.genexprprintSegmentsfontTools.misc.bezierTools.printSegmentsfontTools.misc.bezierTools.__pyx_defaultsfontTools.misc.bezierTools.__pyx_scope_struct__genexprfontTools.misc.bezierTools.__pyx_scope_struct_1_genexprfontTools.misc.bezierTools.__pyx_scope_struct_2_splitCubicAtTCfontTools.misc.bezierTools.__pyx_scope_struct_3__splitCubicAtTCfontTools.misc.bezierTools.__pyx_scope_struct_4_genexprfontTools.misc.bezierTools.__pyx_scope_struct_5__curve_curve_intersections_tfontTools.misc.bezierTools.__pyx_scope_struct_6_genexprfontTools.misc.bezierTools.__pyx_scope_struct_7_genexprbezierToolsInterpreter change detected - this module can only be loaded into one interpreter per process.name__loader__loader__file__origin__package__parent__path__submodule_search_locationsModule 'bezierTools' has already been imported. 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String compression was configured with the C macro 'CYTHON_COMPRESS_STRINGS=%d'.curveCurveIntersections(curve1, curve2) Finds intersections between a curve and a curve. Args: curve1: List of coordinates of the first curve segment as 2D tuples. curve2: List of coordinates of the second curve segment as 2D tuples. Returns: A list of ``Intersection`` objects, each object having ``pt``, ``t1`` and ``t2`` attributes containing the intersection point, time on first segment and time on second segment respectively. Examples:: >>> curve1 = [ (10,100), (90,30), (40,140), (220,220) ] >>> curve2 = [ (5,150), (180,20), (80,250), (210,190) ] >>> intersections = curveCurveIntersections(curve1, curve2) >>> len(intersections) 3 >>> intersections[0].pt (81.7831487395506, 109.88904552375288)solveQuadratic(a, b, c, sqrt=sqrt) Solve a quadratic equation. Solves *a*x*x + b*x + c = 0* where a, b and c are real. Args: a: coefficient of *x²* b: coefficient of *x* c: constant term Returns: A list of roots. Note that the returned list is neither guaranteed to be sorted nor to contain unique values!_curve_curve_intersections_t(curve1, curve2, precision=1e-3, range1=None, range2=None)cubicPointAtT(pt1, pt2, pt3, pt4, t) Finds the point at time `t` on a cubic curve. Args: pt1, pt2, pt3, pt4: Coordinates of the curve as 2D tuples. t: The time along the curve. Returns: A 2D tuple with the coordinates of the point.fontTools.misc.bezierTools.py -- tools for working with Bezier path segments. splitCubic(pt1, pt2, pt3, pt4, where, isHorizontal) Split a cubic Bezier curve at a given coordinate. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as 2D tuples. where: Position at which to split the curve. isHorizontal: Direction of the ray splitting the curve. If true, ``where`` is interpreted as a Y coordinate; if false, then ``where`` is interpreted as an X coordinate. Returns: A list of two curve segments (each curve segment being four 2D tuples) if the curve was successfully split, or a list containing the original curve. Example:: >>> printSegments(splitCubic((0, 0), (25, 100), (75, 100), (100, 0), 150, False)) ((0, 0), (25, 100), (75, 100), (100, 0)) >>> printSegments(splitCubic((0, 0), (25, 100), (75, 100), (100, 0), 50, False)) ((0, 0), (12.5, 50), (31.25, 75), (50, 75)) ((50, 75), (68.75, 75), (87.5, 50), (100, 0)) >>> printSegments(splitCubic((0, 0), (25, 100), (75, 100), (100, 0), 25, True)) ((0, 0), (2.29379, 9.17517), (4.79804, 17.5085), (7.47414, 25)) ((7.47414, 25), (31.2886, 91.6667), (68.7114, 91.6667), (92.5259, 25)) ((92.5259, 25), (95.202, 17.5085), (97.7062, 9.17517), (100, 1.77636e-15))p_segmentrepr(obj) >>> _segmentrepr([1, [2, 3], [], [[2, [3, 4], [0.1, 2.2]]]]) '(1, (2, 3), (), ((2, (3, 4), (0.1, 2.2))))'_both_points_are_on_same_side_of_origin(a, b, origin)splitCubicAtTC(double complex pt1, double complex pt2, double complex pt3, double complex pt4, *ts) Split a cubic Bezier curve at one or more values of t. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as complex numbers.. *ts: Positions at which to split the curve. Yields: Curve segments (each curve segment being four complex numbers).solveCubic(a, b, c, d) Solve a cubic equation. Solves *a*x*x*x + b*x*x + c*x + d = 0* where a, b, c and d are real. Args: a: coefficient of *x³* b: coefficient of *x²* c: coefficient of *x* d: constant term Returns: A list of roots. Note that the returned list is neither guaranteed to be sorted nor to contain unique values! Examples:: >>> solveCubic(1, 1, -6, 0) [-3.0, -0.0, 2.0] >>> solveCubic(-10.0, -9.0, 48.0, -29.0) [-2.9, 1.0, 1.0] >>> solveCubic(-9.875, -9.0, 47.625, -28.75) [-2.911392, 1.0, 1.0] >>> solveCubic(1.0, -4.5, 6.75, -3.375) [1.5, 1.5, 1.5] >>> solveCubic(-12.0, 18.0, -9.0, 1.50023651123) [0.5, 0.5, 0.5] >>> solveCubic( ... 9.0, 0.0, 0.0, -7.62939453125e-05 ... ) == [-0.0, -0.0, -0.0] TrueapproximateQuadraticArcLengthC(double complex pt1, double complex pt2, double complex pt3) Calculates the arc length for a quadratic Bezier segment. Uses Gauss-Legendre quadrature for a branch-free approximation. See :func:`calcQuadraticArcLength` for a slower but more accurate result. Args: pt1: Start point of the Bezier as a complex number. pt2: Handle point of the Bezier as a complex number. pt3: End point of the Bezier as a complex number. Returns: Approximate arc length value._split_cubic_into_two(p0, p1, p2, p3)_splitQuadraticAtT(a, b, c, *ts)_split_segment_at_t(c, t)_is_linelike(segment)lineLineIntersections(s1, e1, s2, e2) Finds intersections between two line segments. Args: s1, e1: Coordinates of the first line as 2D tuples. s2, e2: Coordinates of the second line as 2D tuples. Returns: A list of ``Intersection`` objects, each object having ``pt``, ``t1`` and ``t2`` attributes containing the intersection point, time on first segment and time on second segment respectively. Examples:: >>> a = lineLineIntersections( (310,389), (453, 222), (289, 251), (447, 367)) >>> len(a) 1 >>> intersection = a[0] >>> intersection.pt (374.44882952482897, 313.73458370177315) >>> (intersection.t1, intersection.t2) (0.45069111555824465, 0.5408153767394238)quadraticPointAtT(pt1, pt2, pt3, t) Finds the point at time `t` on a quadratic curve. Args: pt1, pt2, pt3: Coordinates of the curve as 2D tuples. t: The time along the curve. Returns: A 2D tuple with the coordinates of the point.splitLine(pt1, pt2, where, isHorizontal) Split a line at a given coordinate. Args: pt1: Start point of line as 2D tuple. pt2: End point of line as 2D tuple. where: Position at which to split the line. isHorizontal: Direction of the ray splitting the line. If true, ``where`` is interpreted as a Y coordinate; if false, then ``where`` is interpreted as an X coordinate. Returns: A list of two line segments (each line segment being two 2D tuples) if the line was successfully split, or a list containing the original line. Example:: >>> printSegments(splitLine((0, 0), (100, 100), 50, True)) ((0, 0), (50, 50)) ((50, 50), (100, 100)) >>> printSegments(splitLine((0, 0), (100, 100), 100, True)) ((0, 0), (100, 100)) >>> printSegments(splitLine((0, 0), (100, 100), 0, True)) ((0, 0), (0, 0)) ((0, 0), (100, 100)) >>> printSegments(splitLine((0, 0), (100, 100), 0, False)) ((0, 0), (0, 0)) ((0, 0), (100, 100)) >>> printSegments(splitLine((100, 0), (0, 0), 50, False)) ((100, 0), (50, 0)) ((50, 0), (0, 0)) >>> printSegments(splitLine((0, 100), (0, 0), 50, True)) ((0, 100), (0, 50)) ((0, 50), (0, 0))_calcCubicArcLengthCRecurse(double mult, double complex p0, double complex p1, double complex p2, double complex p3)approximateQuadraticArcLength(pt1, pt2, pt3) Calculates the arc length for a quadratic Bezier segment. Uses Gauss-Legendre quadrature for a branch-free approximation. See :func:`calcQuadraticArcLength` for a slower but more accurate result. Args: pt1: Start point of the Bezier as 2D tuple. pt2: Handle point of the Bezier as 2D tuple. pt3: End point of the Bezier as 2D tuple. Returns: Approximate arc length value.approximateCubicArcLength(pt1, pt2, pt3, pt4) Approximates the arc length for a cubic Bezier segment. Uses Gauss-Lobatto quadrature with n=5 points to approximate arc length. See :func:`calcCubicArcLength` for a slower but more accurate result. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as 2D tuples. Returns: Arc length value. Example:: >>> approximateCubicArcLength((0, 0), (25, 100), (75, 100), (100, 0)) 190.04332968932817 >>> approximateCubicArcLength((0, 0), (50, 0), (100, 50), (100, 100)) 154.8852074945903 >>> approximateCubicArcLength((0, 0), (50, 0), (100, 0), (150, 0)) # line; exact result should be 150. 149.99999999999991 >>> approximateCubicArcLength((0, 0), (50, 0), (100, 0), (-50, 0)) # cusp; exact result should be 150. 136.9267662156362 >>> approximateCubicArcLength((0, 0), (50, 0), (100, -50), (-50, 0)) # cusp 154.80848416537057calcCubicBounds(pt1, pt2, pt3, pt4) Calculates the bounding rectangle for a quadratic Bezier segment. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as 2D tuples. Returns: A four-item tuple representing the bounding rectangle ``(xMin, yMin, xMax, yMax)``. Example:: >>> calcCubicBounds((0, 0), (25, 100), (75, 100), (100, 0)) (0, 0, 100, 75.0) >>> calcCubicBounds((0, 0), (50, 0), (100, 50), (100, 100)) (0.0, 0.0, 100, 100) >>> print("%f %f %f %f" % calcCubicBounds((50, 0), (0, 100), (100, 100), (50, 0))) 35.566243 0.000000 64.433757 75.000000curveLineIntersections(curve, line) Finds intersections between a curve and a line. Args: curve: List of coordinates of the curve segment as 2D tuples. line: List of coordinates of the line segment as 2D tuples. Returns: A list of ``Intersection`` objects, each object having ``pt``, ``t1`` and ``t2`` attributes containing the intersection point, time on first segment and time on second segment respectively. Examples:: >>> curve = [ (100, 240), (30, 60), (210, 230), (160, 30) ] >>> line = [ (25, 260), (230, 20) ] >>> intersections = curveLineIntersections(curve, line) >>> len(intersections) 3 >>> intersections[0].pt (84.9000930760723, 189.87306176459828)segmentPointAtT(seg, t)splitQuadratic(pt1, pt2, pt3, where, isHorizontal) Split a quadratic Bezier curve at a given coordinate. Args: pt1,pt2,pt3: Control points of the Bezier as 2D tuples. where: Position at which to split the curve. isHorizontal: Direction of the ray splitting the curve. If true, ``where`` is interpreted as a Y coordinate; if false, then ``where`` is interpreted as an X coordinate. Returns: A list of two curve segments (each curve segment being three 2D tuples) if the curve was successfully split, or a list containing the original curve. Example:: >>> printSegments(splitQuadratic((0, 0), (50, 100), (100, 0), 150, False)) ((0, 0), (50, 100), (100, 0)) >>> printSegments(splitQuadratic((0, 0), (50, 100), (100, 0), 50, False)) ((0, 0), (25, 50), (50, 50)) ((50, 50), (75, 50), (100, 0)) >>> printSegments(splitQuadratic((0, 0), (50, 100), (100, 0), 25, False)) ((0, 0), (12.5, 25), (25, 37.5)) ((25, 37.5), (62.5, 75), (100, 0)) >>> printSegments(splitQuadratic((0, 0), (50, 100), (100, 0), 25, True)) ((0, 0), (7.32233, 14.6447), (14.6447, 25)) ((14.6447, 25), (50, 75), (85.3553, 25)) ((85.3553, 25), (92.6777, 14.6447), (100, -7.10543e-15)) >>> # XXX I'm not at all sure if the following behavior is desirable: >>> printSegments(splitQuadratic((0, 0), (50, 100), (100, 0), 50, True)) ((0, 0), (25, 50), (50, 50)) ((50, 50), (50, 50), (50, 50)) ((50, 50), (75, 50), (100, 0))_curve_line_intersections_t(curve, line)_splitCubicAtT(a, b, c, d, *ts)calcCubicParameters(pt1, pt2, pt3, pt4)calcQuadraticParameters(pt1, pt2, pt3)linePointAtT(pt1, pt2, t) Finds the point at time `t` on a line. Args: pt1, pt2: Coordinates of the line as 2D tuples. t: The time along the line. Returns: A 2D tuple with the coordinates of the point.splitCubicAtT(pt1, pt2, pt3, pt4, *ts) Split a cubic Bezier curve at one or more values of t. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as 2D tuples. *ts: Positions at which to split the curve. Returns: A list of curve segments (each curve segment being four 2D tuples). Examples:: >>> printSegments(splitCubicAtT((0, 0), (25, 100), (75, 100), (100, 0), 0.5)) ((0, 0), (12.5, 50), (31.25, 75), (50, 75)) ((50, 75), (68.75, 75), (87.5, 50), (100, 0)) >>> printSegments(splitCubicAtT((0, 0), (25, 100), (75, 100), (100, 0), 0.5, 0.75)) ((0, 0), (12.5, 50), (31.25, 75), (50, 75)) ((50, 75), (59.375, 75), (68.75, 68.75), (77.3438, 56.25)) ((77.3438, 56.25), (85.9375, 43.75), (93.75, 25), (100, 0))calcCubicPoints(a, b, c, d)calcQuadraticArcLengthC(double complex pt1, double complex pt2, double complex pt3) Calculates the arc length for a quadratic Bezier segment. Args: pt1: Start point of the Bezier as a complex number. pt2: Handle point of the Bezier as a complex number. pt3: End point of the Bezier as a complex number. Returns: Arc length value.calcQuadraticPoints(a, b, c)calcQuadraticArcLength(pt1, pt2, pt3) Calculates the arc length for a quadratic Bezier segment. Args: pt1: Start point of the Bezier as 2D tuple. pt2: Handle point of the Bezier as 2D tuple. pt3: End point of the Bezier as 2D tuple. Returns: Arc length value. Example:: >>> calcQuadraticArcLength((0, 0), (0, 0), (0, 0)) # empty segment 0.0 >>> calcQuadraticArcLength((0, 0), (50, 0), (80, 0)) # collinear points 80.0 >>> calcQuadraticArcLength((0, 0), (0, 50), (0, 80)) # collinear points vertical 80.0 >>> calcQuadraticArcLength((0, 0), (50, 20), (100, 40)) # collinear points 107.70329614269008 >>> calcQuadraticArcLength((0, 0), (0, 100), (100, 0)) 154.02976155645263 >>> calcQuadraticArcLength((0, 0), (0, 50), (100, 0)) 120.21581243984076 >>> calcQuadraticArcLength((0, 0), (50, -10), (80, 50)) 102.53273816445825 >>> calcQuadraticArcLength((0, 0), (40, 0), (-40, 0)) # collinear points, control point outside 66.66666666666667 >>> calcQuadraticArcLength((0, 0), (40, 0), (0, 0)) # collinear points, looping back 40.0calcCubicArcLength(pt1, pt2, pt3, pt4, tolerance=0.005) Calculates the arc length for a cubic Bezier segment. Whereas :func:`approximateCubicArcLength` approximates the length, this function calculates it by "measuring", recursively dividing the curve until the divided segments are shorter than ``tolerance``. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as 2D tuples. tolerance: Controls the precision of the calcuation. Returns: Arc length value.calcQuadraticBounds(pt1, pt2, pt3) Calculates the bounding rectangle for a quadratic Bezier segment. Args: pt1: Start point of the Bezier as a 2D tuple. pt2: Handle point of the Bezier as a 2D tuple. pt3: End point of the Bezier as a 2D tuple. Returns: A four-item tuple representing the bounding rectangle ``(xMin, yMin, xMax, yMax)``. Example:: >>> calcQuadraticBounds((0, 0), (50, 100), (100, 0)) (0, 0, 100, 50.0) >>> calcQuadraticBounds((0, 0), (100, 0), (100, 100)) (0.0, 0.0, 100, 100)_curve_bounds(c)splitCubicIntoTwoAtTC(double complex pt1, double complex pt2, double complex pt3, double complex pt4, double t) Split a cubic Bezier curve at t. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as complex numbers. t: Position at which to split the curve. Returns: A tuple of two curve segments (each curve segment being four complex numbers)._alignment_transformation(segment)segmentSegmentIntersections(seg1, seg2) Finds intersections between two segments. Args: seg1: List of coordinates of the first segment as 2D tuples. seg2: List of coordinates of the second segment as 2D tuples. Returns: A list of ``Intersection`` objects, each object having ``pt``, ``t1`` and ``t2`` attributes containing the intersection point, time on first segment and time on second segment respectively. Examples:: >>> curve1 = [ (10,100), (90,30), (40,140), (220,220) ] >>> curve2 = [ (5,150), (180,20), (80,250), (210,190) ] >>> intersections = segmentSegmentIntersections(curve1, curve2) >>> len(intersections) 3 >>> intersections[0].pt (81.7831487395506, 109.88904552375288) >>> curve3 = [ (100, 240), (30, 60), (210, 230), (160, 30) ] >>> line = [ (25, 260), (230, 20) ] >>> intersections = segmentSegmentIntersections(curve3, line) >>> len(intersections) 3 >>> intersections[0].pt (84.9000930760723, 189.87306176459828)calcCubicArcLengthC(double complex pt1, double complex pt2, double complex pt3, double complex pt4, double tolerance=0.005) Calculates the arc length for a cubic Bezier segment. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as complex numbers. tolerance: Controls the precision of the calcuation. Returns: Arc length value.approximateCubicArcLengthC(double complex pt1, double complex pt2, double complex pt3, double complex pt4) Approximates the arc length for a cubic Bezier segment. Args: pt1,pt2,pt3,pt4: Control points of the Bezier as complex numbers. Returns: Arc length value._line_t_of_pt(s, e, pt)splitQuadraticAtT(pt1, pt2, pt3, *ts) Split a quadratic Bezier curve at one or more values of t. Args: pt1,pt2,pt3: Control points of the Bezier as 2D tuples. *ts: Positions at which to split the curve. Returns: A list of curve segments (each curve segment being three 2D tuples). Examples:: >>> printSegments(splitQuadraticAtT((0, 0), (50, 100), (100, 0), 0.5)) ((0, 0), (25, 50), (50, 50)) ((50, 50), (75, 50), (100, 0)) >>> printSegments(splitQuadraticAtT((0, 0), (50, 100), (100, 0), 0.5, 0.75)) ((0, 0), (25, 50), (50, 50)) ((50, 50), (62.5, 50), (75, 37.5)) ((75, 37.5), (87.5, 25), (100, 0))cubicPointAtTC(double complex pt1, double complex pt2, double complex pt3, double complex pt4, double t) Finds the point at time `t` on a cubic curve. Args: pt1, pt2, pt3, pt4: Coordinates of the curve as complex numbers. t: The time along the curve. 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